I have the following code:
public class Info
{
public string Name;
public string Num;
}
string s1 = "a,b";
string s2 = "1,2";
IEnumerable<Info> InfoSrc =
from name in s1.Split(',')
from num in s2.Split(',')
select new Info()
{
Name = name,
Num = num
};
List<Info> listSrc = InfoSrc.ToList();
I would like my listSrc
result to contain two Info
items whose Name
and Num
properties are:
a, 1
b, 2
However, the code I show above results in four items:
a, 1
a, 2
b, 1
b, 2
You can use Enumerable.Zip
:
IEnumerable<Info> InfoSrc = s1.Split(',')
.Zip(s2.Split(','), (name, num) => new Info(){ Name = name, Num = num });
If you need to map more than two collections to properties you could chain multiple Zip
together with an anonymous type holding the second and third:
IEnumerable<Info> InfoSrc = s1.Split(',')
.Zip(s2.Split(',').Zip(s3.Split(','), (second, third) => new { second, third }),
(first, x) => new Info { Name = first, Num = x.second, Prop3 = x.third });
Here is a hopefully more readable version:
var arrays = new List<string[]> { s1.Split(','), s2.Split(','), s3.Split(',') };
int minLength = arrays.Min(arr => arr.Length); // to be safe, same behaviour as Zip
IEnumerable<Info> InfoSrc = Enumerable.Range(0, minLength)
.Select(i => new Info
{
Name = arrays[0][i],
Num = arrays[1][i],
Prop3 = arrays[2][i]
});
假设项目在每个列表的数量是相等的,它看起来像你试图邮编在一起......
s1.Split(',').Zip(s2.Split(','), (name, num) => new Info{Name = name, Num = num})
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.