int *ar[3];
int x;
for (x == 0; x < 3; ++x)
printf("AR[%d]: %d\n", x, ar[x]);
this returns
AR[0]: 0
AR[1]: 0
AR[2]: 4196432
"int *ar[3]" means array of pointers, its element is a pointer to int, and there is no assignment for this array, that means its element might be any garbage. BTW, the type of ar[x] is pointer, if you want to print ar[x], you should use "%p" instead of "%d", otherwise there is a vast from %p to %d, and the value maybe is not you expect.
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