Fetch rows from database table android

Question

I'm trying to return the array of rows where the username matches the username in the database table. The JSON result just gives me the last row.

example table:

james 14 u@aol.com

mah 12 j@aol.com

james 23 ra@yahoo.com

result gives me:
23 ra@yahoo.com

but i want both james rows not just the last one. so both 14 u@aol.com and 23 ra@yahoo.com thanks

My php code:

<?php 
    $username = $_POST["username"];

    $con = new mysqli("xx", "xx", "xx", "xx");


    // selects everything 
    $statement = mysqli_prepare($con, "SELECT * FROM `user` WHERE username = ?");
    mysqli_stmt_bind_param($statement, "s", $username);

    mysqli_stmt_execute($statement);
    // Store the result to use
    mysqli_stmt_store_result($statement);
    mysqli_stmt_bind_result($statement, $id, $username, $age, $email);

    // Get results returned and put in array
    $user = array();
    while (mysqli_stmt_fetch($statement)) {
        $user[age] = $age;
        $user[email] = $email;
    }

    // Send array back to phone
    print (json_encode($user));

    mysqli_stmt_close($statement);
    mysqli_close($con);

?>

Answer 1

您的数组应该为空，不像[age] [email]那样，它应该为空，以便数组创建索引。

Answer 2

You overwrite the array so try something like this

while (mysqli_stmt_fetch($statement)) {
        $user[] = array( 'age'=>$age, 'email'=>$email);
    }

Answer 3

user[] should be a 2 dimensional array.

In your case last element will be there in the array.

while (mysqli_stmt_fetch($statement)) {
        $user[] = array('age'=>$age,'email' =>$email);
    }

Hope this helps.