How to sort the following xml according to the name alphabetically and convert it into the JSON in Java?

Question

<breakfast_menu>
<food>
    <name>Belgian Waffles</name>
    <price>$5.95</price>
    <description>
    Two of our famous Belgian Waffles with plenty of real maple syrup
    </description>
    <calories>650</calories>
</food>
<food>
    <name>Strawberry Belgian Waffles</name>
    <price>$7.95</price>
    <description>
    Light Belgian waffles covered with strawberries and whipped cream
    </description>
    <calories>900</calories>
</food>
<food>
    <name>Berry-Berry Belgian Waffles</name>
    <price>$8.95</price>
    <description>
    Light Belgian waffles covered with an assortment of fresh berries and whipped cream
    </description>
    <calories>900</calories>
</food>
<food>
    <name>French Toast</name>
    <price>$4.50</price>
    <description>
    Thick slices made from our homemade sourdough bread
    </description>
    <calories>600</calories>
</food>
</breakfast_menu>

I am getting stucked while sorting the xml alphabetically and convert it into the JSON array. The breakfast_menu needs to be sorted by name

Answer 1

If you are using Java 8 , you should check out my open source library: unXml . unXml basically maps from Xpaths to Json-attributes.

It's available on Maven Central .

Example

import java.util.stream.StreamSupport;
import java.util.stream.Collectors;
import com.fasterxml.jackson.databind.node.ObjectNode;
import com.nerdforge.unxml.factory.ParsingFactory;
import com.nerdforge.unxml.parsers.Parser;
import org.w3c.dom.Document;

public class Parser {
    public List<JsonNode> parseXml(String xml){
        Document document = parsing.xml().document(xml);

        // parsing xml to Json
        Parser<ArrayNode> parser = parsing.arr("/breakfast_menu/food")
          .attribute("name")
          .attribute("price")
          .attribute("description")
          .attribute("calories")
          .build();

          ArrayNode jsonArray = parser.apply(document);

          // sorting
          List<JsonNode> result = StreamSupport.stream(jsonArray.spliterator(), false)
            .sorted((first, second) -> first.get("name").asText().compareTo(second.get("name").asText()))
            .collect(Collectors.toList());

        return result;
    }
}

It will return a List of Jackson JsonNode .

[{
    "price" : "$5.95",
    "name" : "Belgian Waffles",
    "description" : " Two of our famous Belgian Waffles with plenty of real maple syrup ",
    "calories" : "650"
}, 
{
    "price" : "$8.95",
    "name" : "Berry-Berry Belgian Waffles",
    "description" : " Light Belgian waffles covered with an assortment of fresh berries and whipped cream ",
    "calories" : "900"
}, 
{
    "price" : "$4.50",
    "name" : "French Toast",
    "description" : " Thick slices made from our homemade sourdough bread ",
    "calories" : "600"
}, 
{
    "price" : "$7.95",
    "name" : "Strawberry Belgian Waffles",
    "description" : " Light Belgian waffles covered with strawberries and whipped cream ",
    "calories" : "900"
}]