Get specified row ranking number

Question

Here is the rows looks like:

Id  Gold
1   200
2   100
3   300
4   900
5   800
6   1000

What I want to achieve is getting the rank number whose Id equals to 5 , which is order by Gold descending.

So after ordering, the intermediate rows should be(NOT RETURN):

Id  Gold
6   1000
4   900
5   800

And the SQL should just return 3 , which is the ranking of Id = 5 row.

What is the most efficient way to achieve this?

Answer 1

You simply want top , I think:

select top 3 t.*
from t
order by gold desc;

If you want the ranking of id = 5 :

select count(*)
from t
where t.gold >= (select t2.gold from t t2 where t2.id = 5);

Answer 2

Try This Code By using Dense_rank ():

WITH cte
     AS (SELECT *,
                Dense_rank()
                  OVER(
                    ORDER BY [Gold] DESC) AS rank
         FROM   your_table)
SELECT rank
FROM   cte
WHERE  id = 5