HI I am trying to query the distinct localities in my table.
Here is my query.
select distinct city,locality, avg_sqft from real_estate.re_search where city = 'bangalore' AND locality != 'jayanagar';
Result
+-----------+--------------+----------+
| city | locality | avg_sqft |
+-----------+--------------+----------+
| bangalore | bannerghatta | 13500 |
| bangalore | kormangala | 18000 |
| bangalore | kodipur | 7000 |
| bangalore | kormangala | 16000 |
| bangalore | horamavu | 9000 |
| bangalore | bellandur | 15500 |
| bangalore | kodipur | 9000 |
| bangalore | madivala | 12000 |
| bangalore | varthur | 12000 |
| bangalore | kormangala | 13500 |
| bangalore | bellandur | 13000 |
| bangalore | kodipur | 11500 |
| bangalore | kormangala | 14000 |
the problem is I need to display the distinct locality in result.any help will be appreciated.
You should be able to get a list of distinct members of the locality column in your table, where the city is Bangalore by using the COUNT
and GROUP BY
operators:
SELECT city
,locality
,COUNT(locality)
FROM database.table
WHERE city = 'Bangalore'
GROUP BY city
,locality;
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