Splitting string into pair of characters in Ruby

Question

我有一个字符串（例如“AABBCCDDEEFF”）并希望将其拆分为一个数组，每个元素包含两个字符 - [“AA”，“BB”，“CC”，“DD”，“EE”，“FF”] 。

Answer 1

Try the String object's scan method:

>> foo = "AABBCCDDEEFF"
=> "AABBCCDDEEFF"
>> foo.scan(/../)
=> ["AA", "BB", "CC", "DD", "EE", "FF"]

Answer 2

Depending on your needs, this may work better:

>  foo = "AAABBCDEEFF"
=> "AAABBCDEEFF"
> foo.scan(/.{1,2}/)
=> ["AA", "AB", "BC", "DE", "EF", "F"]

Not sure what your input looks like. The above answer will drop any characters that do not have a pair, this one will work on odd length strings.