Regexp, replace certain combinations

Question

Got this string: "'ab',('AA', 'BB'), r('rr')"

I want the output to be "'ab',['AA', 'BB'], r('rr')"

Tried this

var replace = function(str){
    return str.replace(/\)/g, ']')
  .replace(/\(/g, '[')
}

It replaces all paranthes but how do I combine the regexp so it only replaces ,( with [ ?

https://jsfiddle.net/tyapco67/

Answer 1

只需在括号前添加逗号：

return str.replace(/(,\s*)\((.*?)\)/g, '$1[$2]');

Answer 2

没有RegEx

"'ab',('AA', 'BB'), r('rr')".split(",(").join(",[").split("),").join("],")

Answer 3

I like to use the [^]* inverse selector personally. Thus it doesn't require the comma.

var replace = function(str){
    return str.replace(/\(([^)]*)\)/g, "[$1]");
}

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The currently accepted answer would produce 'ab',['AA', 'BB'], r('rr') .