How Can I return both number of ints less than or equal to average and number of ints greater than average

Question

I am new to functions. I don't know how can I output numbers of ints less than or equal to average and number of ints greater than average. How I need to call my function so that it output both results ?

int compareAverage(int numbers[], int count, double average)
{
    int lessEqualCount = 0;
    int greaterCount = 0;

    for (int i = 0; i < count; i ++)
       {
           if (numbers[i] <= average){
               lessEqualCount++;
               return lessEqualCount;}


           else{
              greaterCount++;
              return greaterCount;}
       }

Answer 1

There are several solutions.
The first ones that come to my mind:

• accept to pointers to int in which to write the results
• return a std::pair of int s instead of a single value
• return a struct having two properties for the two values
• return an array (either a naked one or a std::array ) containing the two values
• ...

It follows an example:

std::pair<int, int> compareAverage(int numbers[], int count, double average) {
    std::pair<int, int> ret = std::make_pair<int, int>(0, 0);

    for (int i = 0; i < count; i ++) {
        if (numbers[i] <= average) {
            ret.first++;
        } else {
            ret.second++;
        }
    }

    return ret;
}