I am trying to take two arguments from the command line, the first number is the starting point, and the second one is how many prime numbers should be found after that. I need to print the prime numbers found as many times as the second command argument says. I cannot figure out how to make it run the correct amount of times, and after that find the prime number. Here is what I have tried:
int values = Integer.parseInt(args[0]);
int loopAmount = Integer.parseInt(args[1]);
for (int i = 2; i <= loopAmount; i++) {
loopAmount++;
if (values % i != 0) {
values++;
System.out.println(i);
}
}
Your main loop should be something like this:
int start = Integer.parseInt(args[0]);
int count = Integer.parseInt(args[1]);
for (int candidate = start, i = 0; i < count; ++candidate) {
if (isPrime(candidate)) {
i++;
System.out.println(candidate);
}
}
I replaced the variable names to make them more meaningful about their purpose.
Inside the loop, the isPrime
method is something you'll have to implement: if the parameter it receives is a prime, return true
, otherwise false
.
If I understand correctly you want to find N prime numbers starting from X. Code should be pretty simple:
int X = Integer.parseInt(args[0]);
int N = Integer.parseInt(args[1]);
int C = 0;
while (C < N)
{
for(int i=2; i< X; i++)
{
if(X % i == 0){
X++;
continue;
}
}
System.out.println(X);
X++;
C++;
}
An optimized version :
// cache already found primes
final List<Integer> primes = new ArrayList<>();
/**
* Find {@code count} prime numbers starting at {@code start} inclusive
*/
public void findPrimes(int start, int count) {
for (int i = 2; count > 0; i++) {
if (isPrime(i) && i >= start) {
System.out.println(i);
count--;
}
}
}
private boolean isPrime(final int i) {
int sqrt = (int)Math.sqrt(i);
for (int prime : primes) {
if (i % prime == 0) {
return false;
}
if (prime > sqrt) {
break;
}
}
primes.add(i);
return true;
}
solution
#include <iostream>
using namespace std;
int main() {
int i, n;
bool isPrime = true;
cout << "Enter a positive integer: ";
cin >> n;
// 0 and 1 are not prime numbers
if (n == 0 || n == 1)
{
isPrime = false;
}
else
{
//algorithm to check for prime numbers
for (i = 2; i <= n / 2; ++i)
{
if (n % i == 0)
{
isPrime = false;
break;
}
}
}
if (isPrime)
cout << n << " is a prime number";
else
cout << n << " is not a prime number";
return 0;
}
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