How to calculate week ending date in hive using Saturday as week ending date?

Question

I had a scenario where I wanted to calculate week ending date (given a date), considering week ends at Saturday. I read some answers but could not find the solution, so I am posting my approach here. Hope it helps somebody like me.

select 
TransactionDateTime,
from_unixtime(unix_timestamp(TransactionTime),'u') as wkday,
date_add (TransactionDateTime,
case when from_unixtime(unix_timestamp(TransactionTime),'u')=7 then 6 
when from_unixtime(unix_timestamp(TransactionTime),'u')=1 then 5
when from_unixtime(unix_timestamp(TransactionTime),'u')=2 then 4
when from_unixtime(unix_timestamp(TransactionTime),'u')=3 then 3
when from_unixtime(unix_timestamp(TransactionTime),'u')=4 then 2
when from_unixtime(unix_timestamp(TransactionTime),'u')=5 then 1
when from_unixtime(unix_timestamp(TransactionTime),'u')=6 then 0
end) as UsageWkEndDt
from TransTable;

Answer 1

select 
TransactionDateTime,
from_unixtime(unix_timestamp(TransactionTime),'u') as wkday,
date_add (TransactionDateTime,
case when from_unixtime(unix_timestamp(TransactionTime),'u')=7 then 6 
when from_unixtime(unix_timestamp(TransactionTime),'u')=1 then 5
when from_unixtime(unix_timestamp(TransactionTime),'u')=2 then 4
when from_unixtime(unix_timestamp(TransactionTime),'u')=3 then 3
when from_unixtime(unix_timestamp(TransactionTime),'u')=4 then 2
when from_unixtime(unix_timestamp(TransactionTime),'u')=5 then 1
when from_unixtime(unix_timestamp(TransactionTime),'u')=6 then 0
end) as UsageWkEndDt
from TransTable;