Regex to match everything after the last occurrence of a string

Question

Struggling to find a way to do this so any help appreciated.

Have simple text on single line - and want to match all of the text after the final </p> tag.

I'm using regex in Open Office - so I need to return a direct match rather than a javascript array.

String looks like this:

<p>Foo bar bar bar foo</p> <p>Foo bar bar foo</p> This Foo bar foo bar <br>

I can match INCLUDING the final </p> like this:

<\/p>(?!.*<\/p>).*$

I can match it in php regex flavour like this:

(?<=<\/p>(?!.*<\/p>))(.*)(?=$)

And I can get close using this - but it only matches at the first < - not the whole </p> string:

(?!.*<\/p>)(.*)(?=$)

Driving me crazy so any help appreciated.

Thanks

Sorry - yes did see the duplicate question but couldn't get it to work - so they said these solutions for their problem:

.*\[\/quote\](.*)$

[\s\S]*\[\/quote\]([\s\S]*)$

Which I transposed to my problem to look like this:

.*<\/p>(.*)$

[\s\S]*<\/p>([\s\S]*)$

Neither of which I could get to work with open office regex - so hence the question.

Answer 1

Sorry I did not catch you wanted after:

</p>

Using this:

.*<\/p>(.*)$

You have an array where the second element is what you look for.

Tested code:

var text = '<p>Foo bar bar bar foo</p> <p>Foo bar bar foo</p> This Foo bar foo bar <br>';
var patt = new RegExp(".*<\/p>(.*)$");
var matched = patt.exec(text);

Tester:

http://www.pythontutor.com/javascript.html#mode=edit

Result: