RegEx that will match the last occurrence of dot in a string

Question

I have a filename that can have multiple dots in it and could end with any extension:

tro.lo.lo.lo.lo.lo.png

I need to use a regex to replace the last occurrence of the dot with another string like @2x and then the dot again (very much like a retina image filename) ie:

tro.lo.png -> tro.lo@2x.png

Here's what I have so far but it won't match anything...

str = "http://example.com/image.png";
str.replace(/.([^.]*)$/, " @2x.");

any suggestions?

Answer 1

You do not need a regex for this. String.lastIndexOf will do.

var str = 'tro.lo.lo.lo.lo.lo.zip';
var i = str.lastIndexOf('.');
if (i != -1) {
    str = str.substr(0, i) + "@2x" + str.substr(i);
}

See it in action .

Update: A regex solution, just for the fun of it:

str = str.replace(/\.(?=[^.]*$)/, "@2x.");

Matches a literal dot and then asserts ( (?=) is positive lookahead ) that no other character up to the end of the string is a dot. The replacement should include the one dot that was matched, unless you want to remove it.

Answer 2

Just use special replacement pattern $1 in the replacement string:

 console.log("tro.lo.lo.lo.lo.lo.png".replace(/\\.([^.]+)$/, "@2x.$1")); // "tro.lo.lo.lo.lo.lo@2x.png" 

Answer 3

You can use the expression \\.([^.]*?) :

str.replace(/\.([^.]*?)$/, "@2x.$1");

You need to reference the $1 subgroup to copy the portion back into the resulting string.

Answer 4

working demo http://jsfiddle.net/AbDyh/1/

code

var str = 'tro.lo.lo.lo.lo.lo.zip',
    replacement = '@2x.';
str = str.replace(/.([^.]*)$/, replacement + '$1');

$('.test').html(str);

alert(str);
​

Answer 5

To match all characters from the beginning of the string until (and including) the last occurence of a character use:

^.*\.(?=[^.]*$)  To match the last occurrence of the "." character

^.*_(?=[^.]*$)   To match the last occurrence of the "_" character

Answer 6

Use \\. to match a dot. The character . matches any character.

Therefore str.replace(/\\.([^\\.]*)$/, ' @2x.') .

Answer 7

You could simply do like this,

> "tro.lo.lo.lo.lo.lo.zip".replace(/^(.*)\./, "$1@2x");
'tro.lo.lo.lo.lo.lo@2xzip'

Answer 8

Why not simply split the string and add said suffix to the second to last entry:

var arr = 'tro.lo.lo.lo.lo.lo.zip'.split('.');
arr[arr.length-2] += '@2x';
var newString = arr.join('.');

Answer 9

'tro.lo.lo.lo.lo.lo.png'.replace(/([^\.]+).+(\.[^.]+)/, "$1.@x2$2")