#include <iostream>
using namespace std;
int main()
{
int i;
cout << "Enter: " << endl;
cin >> i;
cout << cin.fail() << endl;
}
This is my typical implementation for error checking to make sure I am entering a valid input and this was what I was taught. The problem with my above code is if I type in '4d' it stores the 4 in variable 'i', but leaves the 'd' in the buffer, so the cin.fail() test returns false, but I want it to return true. If I type in 'c' or 'ccc' etc... cin.fail() returns true as I want.
Is there any proper command to test for what I have described?
I suspect there are more than one ways to solve your problem. I can think of the following two.
Get the next character right after you read i
. If that character is not a whitespace character, you can flag that as an error.
cin >> i; if ( cin ) // reading to i was successful. { int c = cin.get(); if (!isspace(c) ) { // There was a non whitespace character right // after the number. // Treat it as a problem } }
Read a token of characters and check whether any of them is not a digit.
std::string token; cin >> token; for ( auto c : token ) { if (!isdigit(c) ) { // Problem } }
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