How to remove the square brackets from a list when it is printed/output

Question

I have a piece of code that does everything I need it to do and now I am making it look better and refining it. When I print the outcome, I find that the list in the statement is in square brackets and I cannot seem to remove them.

Answer 1

You can use map() to convert the numbers to strings, and use " ".join() or ", ".join() to place them in the same string:

mylist = [4, 5]
print(" ".join(map(str, mylist)))
#4 5
print(", ".join(map(str, mylist)))
#4, 5

You could also just take advantage of the print() function:

mylist = [4, 5]
print(*mylist)
#4 5
print(*mylist, sep=", ")
#4, 5

Note: In Python2, that won't work because print is a statement, not a function. You could put from __future__ import print_function at the beginning of the file, or you could use import __builtin__; getattr(__builtin__, 'print')(*mylist) import __builtin__; getattr(__builtin__, 'print')(*mylist)

Answer 2

If print is a function (which it is by default in Python 3), you could unpack the list with * :

>>> L = [3, 5]
>>> from __future__ import print_function
>>> print(*L)
3 5

Answer 3

You could convert it to a string instead of printing the list directly:

print(", ".join(LIST))

If the elements in the list are not strings, you can convert them to string using either repr() or str() :

LIST = [1, "printing", 3.5, { "without": "brackets" }]
print( ", ".join( repr(e) for e in LIST ) )

Which gives the output:

1, 'printing', 3.5, {'without': 'brackets'}

Answer 4

You could do smth like this:

separator = ','
print separator.join(str(element) for element in myList) 

Answer 5

Why don't you display the elements in the list one by one using the for loop instead of displaying an entire list at once like so:

# l - list
for i in range(0, len(l)):
    print l[i],