My output format is not correct can someone help me?

Question

Given an unsorted list of integers, output the integers in order.

Sample Input

100 63 25 73 1 98 73 56 84 86 57 16 83 8 25 81 56 9 53 98 67 99 12 83 89 80 91 39 86 76 85 74 39 25 90 59 10 94 32 44 3 89 30 27 79 46 96 27 32 18 21 92 69 81 40 40 34 68 78 24 87 42 69 23 41 78 22 6 90 99 89 50 30 20 1 43 3 70 95 33 46 44 9 69 48 33 60 65 16 82 67 61 32 21 79 75 75 13 87 70 33

Sample Output

1 1 3 3 6 8 9 9 10 12 13 16 16 18 20 21 21 22 23 24 25 25 25 27 27 30 30 32 32 32 33 33 33 34 39 39 40 40 41 42 43 44 44 46 46 48 50 53 56 56 57 59 60 61 63 65 67 67 68 69 69 69 70 70 73 73 74 75 75 76 78 78 79 79 80 81 81 82 83 83 84 85 86 86 87 87 89 89 89 90 90 91 92 94 95 96 98 98 99 99

My Output

11 33 6 8 99 10 12 13 1616 18 20 2121 22 23 24 252525 2727 3030 323232 333333 34 3939 4040 41 42 43 4444 4646 48 50 53 5656 57 59 60 61 63 65 6767 68 696969 7070 7373 74 7575 76 7878 7979 80 8181 82 8383 84 85 8686 8787 898989 9090 91 92 94 95 96 9898 9999

my code:

a=int(input())
b=input()
b1=b.split(" ")
arr=list(map(int,b1))
ans=[]
for i in range(0,100,1):
    #print(arr.count(i),end=' ')
    ans.append(arr.count(i))
for i in range(0,len(ans)):
    if(i==0):
        continue
    else:
        print(str(i)*ans[i],end=' ')

Answer 1

如果您必须这样做，请尝试：

print((str(i) + ' ') * ans[i], end=' ')

Answer 2

Use sorted with key:

string = "100 63 25 73 1 98 73 56 84 ... "

sorted_string = " ".join(sorted(string.split(), key=lambda x: int(x)))