I need to ask you something, about my problem.Try to imagine, that a have a string like: "23221323,213213,123213,,,"
I have been looking in several websites, but i dont find anything. I need a regular expression about how to remove the character(,) ..
I mean, i want to remove the last , if its more that 1:
Example:
"2323,3434,2332" ==> its OK
"3434,21321,45454,,,,==> BAD. you have to remove the last 3 , only 1 final is allowed.
Actually i have something in java, that works:
String sCadena="asd,";
CharSequence cs1 = ",,";
CharSequence cs2 = ",,,";
CharSequence cs0 = ",";
if(sCadena.contains(cs2)){
sCadena=sCadena.substring(0, sCadena.length() - 3);
}
else if (sCadena.contains(cs1)){
sCadena=sCadena.substring(0, sCadena.length() - 2);
}
else if (sCadena.contains(cs0)){
sCadena=sCadena.substring(0, sCadena.length() - 1);
}
}
But i want to make a regular expression to avoid this, because if the user enter a lot of (,), i have to implement more if to control this....
Any ideas??
This should work for you :
public static void main(String[] args) {
String s = "23221323,213213,123213,,,";
s = s.replaceAll(",+$",","); // replaces all trailing commas with a single one
System.out.println(s);
}
O/P :
23221323,213213,123213,
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.