How to pass multiple parameters to a program while executing it using start command in command prompt in windows?

Question

When I run the following query, the program opens but it is still asking for parameters instead of it taking the parameters from the start command. I am not running a batch file here, please correct my statement for errors.

START "TESTING" /D "D:\Work\ORMB DB Upgradation work\ORMB_DB_Upgrade_2.3.0.2.0_to_2.4.0.0.0\FW\FW42020\FW42020-HFix47\" /MIN /HIGH CDXPatch.exe "O" "schema_user" "schema_pass" "db_name" "Y"

The discussion so far have yielded the following command as best shot for solution:

echo.O&echo.user&echo.pass&echo.db&echo.Y | "Path\CDXPatch.exe" 

It yielded the following error:

Answer 1

Put this in your main batch file (replace CDXPatch.exe with CDXPatch.bat *):

START "TESTING" /D "D:\Work\ORMB DB Upgradation work\ORMB_DB_Upgrade_2.3.0.2.0_to_2.4.0.0.0\FW\FW42020\FW42020-HFix47\" /MIN /HIGH CDXPatch.bat "O" "schema_user" "schema_pass" "db_name" "Y"

Then put this into CDXPatch.bat (edited to support arbitrary number of arguments):

@(for %%a in (%*) do @echo.%%~a) | CDXPatch.exe

* CXDPatch.bat must be either in a directory specified in %PATH% or you must specify full path (eg. C:\\User\\CDXPatch.bat ).