I'm trying to write a script which will print directories, subdirectories and their files in a tree structure, but without using tree command.
Example:
DIR: A
f1
f2
DIR: B
f3
DIR: C
file1
file21
I have tried multiple of solutions, but I always ran into the problem that I could not distinguish between a directory or a file, therefore I could not apply the right formatting. The "DIR: " prefix makes it complicated. Is there something very obvious that I'm missing?
Use the the -d
test:
if [ -d "$path" ] ; then
echo DIR
fi
Cited from this SO question
Is this what your looking for tree , should be in most distributions (maybe as an optional install)?
~> tree -d /proc/self/
/proc/self/
|-- attr
|-- cwd -> /proc
|-- fd
| `-- 3 -> /proc/15589/fd
|-- fdinfo
|-- net
| |-- dev_snmp6
| |-- netfilter
| |-- rpc
| | |-- auth.rpcsec.context
| | |-- auth.rpcsec.init
| | |-- auth.unix.gid
| | |-- auth.unix.ip
| | |-- nfs4.idtoname
| | |-- nfs4.nametoid
| | |-- nfsd.export
| | `-- nfsd.fh
| `-- stat
|-- root -> /
`-- task
`-- 15589
|-- attr
|-- cwd -> /proc
|-- fd
| `-- 3 -> /proc/15589/task/15589/fd
|-- fdinfo
`-- root -> /
27 directories
sample taken from maintainers web page.
You can add the option -L #
where #
is replaced by a number, to specify the max recursivity level.
Remove -d
to display also files.
您也可以尝试这些命令的变体
find . -type d -print | sed -e 's;[^/]*/;|____;g;s;____|; |;g'
find . -print | sed -e 's;[^/]*/;|____;g;s;____|; |;g'
find . | sed -e 's;[^/]*/;|____;g;s;____|; |;g'
find -type d
tree -l
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