How to print line number that contains specific number?

Question

I have 6000 lines,with one per number float.

My code

awk '5.400000e+03 {print $0}' base.txt

Only prints numbers

5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03
5.400000e+03

I have changed to

awk '{if($0=="5.400000e+03 ") print NR}' base.txt

but then got nothing! What should I try?

Answer 1

You can use:

awk '$1 == "5.400000e+03" {print NR, $0}' base.txt

$1 will always match first column irrespective of spaces or no spaces after shown data in your question. Use print NR, $0 to print each record prefixed with record number.

Answer 2

You can also use grep:

# just the line number
grep -wn "5.400000e+03" base.txt | cut -d: -f1
# both
grep -wn "5.400000e+03" base.txt