Python regex with lookbehind and lookahead not working

Question

I have a Python regex working finely in debuggex :

However, when I do this in a Python console:

import re
rgx = re.compile(r'(?<="careerJobAdsList", ){"jobAds":.*}](?=,"nodes":)')

st = 'widget("careerJobAdsList", {"jobAds":[{"id":607}],"nodes":[{"id":2,"parent_id"'

rgx.match(st)
>>> None

I've tried to escape all special characters in rgx , but it doesn't change the output.

Am I missing something?

Answer 1

match finds match in beginning of string. Use search instead

print(rgx.search(st))

Quoting re.match

If zero or more characters at the beginning of string match the regular expression pattern, return a corresponding MatchObject instance. Return None if the string does not match the pattern; note that this is different from a zero-length match.

Python Code

import re
rgx = re.compile(r'(?<="careerJobAdsList", ){"jobAds":.*}](?=,"nodes":)')
st = 'widget("careerJobAdsList", {"jobAds":[{"id":607}],"nodes":[{"id":2,"parent_id"'
print(rgx.search(st))