Iam new to java and I would like to make a question about java regular expression.
How can I check if a line contains only a specific string followed by any operator. Also, and previous of the string does not contains "//".
For example, if line is:
//x; -> does not matches the criteria
x++; ->matches
x--; ->matches
x=1; ->matches
(x,y) ->matches
(x1,y) ->does not matches because we want only x not x1
x = 1 ; ->matches
Thanks in advance.
You can use this negative lookahead based regex:
^(?:(?!//).)*\bx\b.*
In Java use:
boolean valid = str.matches("^(?:(?!//).)*\\bx\\b");
RegEx Breakup:
^ # line start
(?:(?!//).)* # negative lookahead, match any char that doesn't have // at next position
\b # word boundary
x # literal x
\b # word boundary
.* # match every thing till end
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