Don't match dot in beginning of string

Question

I have one path in form of string like this Folder1/File.png But in this string sometimes if file is hidden or folder is hidden I don't want it to be matched by my regex.

regex = %r{([a-zA-Z0-9_ -]*)\/[^.]+$}

input_path = "Folder_1/.file" # This shouldn't be matched.
input_path = "Folder/file.png" # This should be matched.

But my regex works for first input but its not even matching second one.

Answer 1

You are currently looking for \\/[^.]+$ , that is a / followed by any character except . until the end. Since the filename+extension format has a . character, it fails to match the second case.

Instead of using [^.]+$ , check only that the character following / is not . , and match everything after that:

([a-zA-Z0-9_ -]*)\/[^.].*$

Answer 2

While there are some suggestions here that work, my suggestion would be

\/[^.][^\/\n]+$

It finds a slash , followed by anything but a dot, which in turn is followed by one, or more, of anything but a slash or a newline .

To handle the two lines given as an example,

Folder_1/.file
Folder/file.png

it takes 8 steps.

The suggested ones all work, but ([a-zA-Z0-9_ -]*)\\/[^.] takes 75 steps, ([a-zA-Z0-9_ -]*)\\/[^.]+\\.[^.]+\\z 78 steps and ([a-zA-Z0-9_ -]*)\\/[^.].*$ takes 77 steps.

This may be totally irrelevant and I may have missed some angle, but I wanted to mention it ;)

Se it here at regex101 .

Answer 3

regex = %r{([a-zA-Z0-9_ -]*)\/[^.]}