I found a method to iterate a python dictionary object recursively on this forum. However, I wish to extend that function so that I get a string similar to the structure of a file path. With my function below, I expect an output in the form of
/key1/value1
/key2/value2
/key3/key3a/value3a
/key4/key4a/key4a1/value4a1
/key4/key4a/key4a2/value4a2
/key4/key4a/key4a3/value4a3
/key4/key4b/key4b1/key4b1a/value4b1a
/key4/key4b/key4b1/key4b1b/value4b1b
/key4/key4b/key4b1/key4b1c/value4b1c
/key4/key4c/key4c1/key4c1a/value4c1a
/key4/key4c/key4c1/key4c1b/value4c1b
/key4/key4c/key4c1/key4c1c/value4c1c
Unfortunately, I hit a block. I cannot figure out how to achieve that. Below is the code that I came up with. Any help is greatly appreciated.
import sys
import collections
dict_object = {
'key1': 'value1',
'key2': 'value2',
'key3': {'key3a': 'value3a'},
'key4': {
'key4a': {
'key4a1': 'value4a1',
'key4a2': 'value4a2',
'key4a3': 'value4a3'
},
'key4b': {
'key4b1': {
'key4b1a': 'value4b1a',
'key4b1b': 'value4b1b',
'key4b1c': 'value4b1c'
},
'key4c': {
'key4c1': {
'key4c1a': 'value4c1a',
'key4c1b': 'value4c1b',
'key4c1c': 'value4c1c'
}
}
}
}
}
def print_dict(dictionary, path='', parent=''):
""" This finction recursively prints nested dictionaries."""
#Sort the dictionary object by its keys
if isinstance(dictionary, dict):
dictionary = collections.OrderedDict(sorted(dictionary.items()))
else:
dictionary = sorted(dictionary.items(), key=operator.itemgetter(1))
#iterate each sorted dictionary key
for key, value in dictionary.iteritems():
if isinstance(value, dict):
path = ''
path = '%s/%s/%s' % (path, parent, key)
#Repeat this funtion for nested {} instances
print_dict(value, path, key)
else:
#Print the last node i.e PATH + KEY + VALUE
print '%s/%s/%s' % (path, key, value)
if __name__ == '__main__':
print_dict(dict_object)
Your function appears overly complicated. Only actually print when you have an object that's not a dictionary, otherwise recurse for all values in a dictionary. I simplified path handling to just one string:
def print_dict(ob, path=''):
if not isinstance(ob, dict):
print '{}/{}'.format(path, ob)
else:
for key, value in sorted(ob.items()):
print_dict(value, '{}/{}'.format(path, key))
I didn't bother with creating OrderedDict
objects; all you need is iteration in sorted order.
This produces the expected output:
>>> print_dict(dict_object)
/key1/value1
/key2/value2
/key3/key3a/value3a
/key4/key4a/key4a1/value4a1
/key4/key4a/key4a2/value4a2
/key4/key4a/key4a3/value4a3
/key4/key4b/key4b1/key4b1a/value4b1a
/key4/key4b/key4b1/key4b1b/value4b1b
/key4/key4b/key4b1/key4b1c/value4b1c
/key4/key4b/key4c/key4c1/key4c1a/value4c1a
/key4/key4b/key4c/key4c1/key4c1b/value4c1b
/key4/key4b/key4c/key4c1/key4c1c/value4c1c
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