Passing multiple variables from local bash to remote bash script without gobbling

Question

I'm having trouble sending multiple variables to a remote bash script without gobbling occurring.

For the sake of this question the variable $timestamp contains 12-12-15 19:45:21

ssh user@serverip "/usr/path/to/script.sh http://www.web.com/$1 http://web.com/$2 $timestamp";

I am sending 3 variables to script.sh

Two URLs with an amended file name in the form of a variable on the end and then my $timestamp variable

But on myscript.sh, when I try to insert $timestamp into a mysql database it only see's the first part of the date before the white space :

12-12-15   

So my quotes around the command aren't preventing gobbling. Do I need to quote each variable separately?

Answer 1

ssh user@serverip "/usr/path/to/script.sh http://www.web.com/$1 http://web.com/$2 $timestamp";

This is equivalent to this locally calling

/usr/path/to/script.sh http://www.web.com/$1 http://web.com/$2 $timestamp

Try to quote each individual argument passed

ssh user@serverip "/usr/path/to/script.sh 'http://www.web.com/$1' 'http://web.com/$2' '$timestamp'";

You can also print each argument in the script to see what's being passed... eg echo $1 , etc.

Answer 2

您可以尝试类似

ssh localhost "printf \"%s %s %s\n\" a b \"last parameter\""

Answer 3

You need to escape the values for the remote host. The correct way of doing this is with printf %q :

ssh user@serverip "/usr/path/to/script.sh \
    $(printf "%q " "http://www.web.com/$1" "http://web.com/$2" "$timestamp")"

This works for all variable values. Wrapping them in single quotes would instead result in syntax error and command injection when the variables themselves contain single quotes.