Python sqlite3 order error

Question

So, I am trying to understand this:

    c.execute('SELECT * FROM random ORDER BY id')
    line = c.fetchall()
    for row in line:
        text.insert(END, row)
        text.insert(END, '\n')

With the Sqlite3 list:

1 7

2 94

3 15

(The first number is a simple id (line number for example) and the second number is just a random number) Now, I have a problem...When I add the the id 11 and when i print row it gives me this:

('1', 7)

('11', 60)

('2', 94)

('3', 15)

The number 11 was supposed to appear last, right?

Any help?

Answer 1

看起来列id的类型为char ，因此顺序是正确的，因为字符串11小于2。您应将列ID的类型更改为int或者必须先转换id才能订购

Answer 2

在输出中，您的引号包含11： '11' -这表示它是11的字符串。以某种方式，您需要确保将整数存储在id字段中。