I have the following function:
def getSuggestengineResult(suggestengine, seed, tablename):
table = getTable(tablename)
for keyword_result in results[seed][suggestengine]:
i = 0
while True:
try:
allKeywords.put_item(
Item={
'keyword': keyword_result
}
)
break
except ProvisionedThroughputExceededException as pe:
if (i > 9):
addtoerrortable(keyword_result)
print(pe)
break
sleep(1)
i = i + 1
print("ProvisionedThroughputExceededException in getSugestengineResult")
The function gets started in more then one thread. I have this process and if the process works, the function should be ready in the thread. Otherwise it should try again 9 times. Now my problem: the "print("ProvisionedThroughputExceededException in getSugestengineResult")" Never got printed. Just the exception as pe gets printed. So there is my problem? Are all the threads working on the same "i"? Or is it never possible to get to the print? I dont know what I am doin wrong ...
You have to use a specific counter if you want all your thread to have the same counter :
from multiprocessing import Lock, Process, Value
class ThreadCounter(object):
def __init__(self, initval=0):
self.val = Value('i', initval)
self.lock = Lock()
def increment(self):
with self.lock:
self.val.value += 1
def value(self):
with self.lock:
return self.val
then you can pass the counter to your function
counter=ThreadCounter(0)
def getSuggestengineResult(suggestengine, seed, tablename,counter):
...
except ProvisionedThroughputExceededException as pe:
if (counter.value() > 9):
...
counter.increment()
...
This counter will be shared with the other threads
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