I have a String:
String s = "msqlsum81pv 0 0 25 25 25 2 -sn D:\\workdir\\PV 81\\config\\sum81pv.pwf -C 5000";
I want to get the path (in this case D:\\\\workdir\\\\PV 81\\\\config\\\\sum81pv.pwf
) from this string. This path is an argument of a command option -sn
or -n
, so this path always appears after these options.
The path may or may not contain whitespaces, which needs to be handled.
public class TestClass {
public static void main(String[] args) {
String path;
String s = "msqlsum81pv 0 0 25 25 25 2 -sn D:\\workdir\\PV 81\\config\\sum81pv.pwf -C 5000";
path = s.replaceAll(".*(-sn|-n) \"?([^ ]*)?", "$2");
System.out.println("Path: " + path);
}
}
Current output: Path: D:\\workdir\\PV 81\\config\\sum81pv.pwf -C 5000
Expected output: Path: D:\\workdir\\PV 81\\config\\sum81pv.pwf
Below Answers working fine for the earlier case.
i need a regex which return `*.pwf` path if the option is `-sn, -n, -s, -s -n, or without -s or -n.`
But if I have below case then what would be the regex to find password file.
String s1 = msqllab91 0 0 1 50 50 60 /mti/root/bin/msqlora -n "tmp/my.pwf" -s
String s2 = msqllab92 0 0 1 50 50 60 /mti/root/bin/msqlora -s -n /mti/root/my.pwf
String s3 = msqllab93 0 0 1 50 50 60 msqlora -s -n "/mti/root/my.pwf" -C 10000
String s4 = msqllab94 0 0 1 50 50 60 msqlora.exe -sn /mti/root/my.pwf
String s5 = msqllab95 0 0 1 50 50 60 msqlora.exe -sn "/mti/root"/my.pwf
String s6 = msqllab96 0 0 1 50 50 60 msqlora.exe -sn"/mti/root"/my.pwf
String s7 = msqllab97 0 0 1 50 50 60 "/mti/root/bin/msqlora" -s -n /mti/root/my.pwf -s
String s8 = msqllab98 0 0 1 50 50 60 /mti/root/bin/msqlora -s
String s9 = msqllab99 0 0 1 50 50 60 /mti/root/bin/msqlora -s -n /mti/root/my.NOTpwf -s -n /mti/root/my.pwf
String s10 = msqllab90 0 0 1 50 50 60 /mti/root/bin/msqlora -sn /mti/root/my.NOTpwf -sn /mti/root/my.pwf
String s11 = msqllab901 0 0 1 50 50 60 /mti/root/bin/msqlora
String s12 = msqllab902 0 0 1 50 50 60 /mti/root/msqlora-n NOTmy.pwf
String s13 = msqllab903 0 0 1 50 50 60 /mti/root/msqlora-n.exe NOTmy.pwf
i need a regex which return *.pwf
path if the option is -sn, -n, -s, -s -n, or without -s or -n.
Note: I already asked this type of question but didn't get anything working as per my requirement. ( How to get specific substring with option vale using java )
You can use:
path = s.replaceFirst(".*\\s-s?n\\s*(.+?)(?:\\s-.*|$)", "$1");
//=> D:\workdir\PV 81\config\sum81pv.pwf
Try this
String s = "msqlsum81pv 0 0 25 25 25 2 -sn D:\\workdir\\PV 81\\config\\sum81pv.pwf -C 5000";
int l=s.indexOf("-sn");
int l1=s.indexOf("-C");
System.out.println(s.substring(l+4,l1-2));
You can also use : [AZ]:.*\\.\\w+
Rather than using complex regexps for replacing, I'd rather suggest a simpler one for matching :
String s = "msqlsum81pv 0 0 25 25 25 2 -sn D:\\workdir\\PV 81\\config\\sum81pv.pwf -C 5000";
Pattern pattern = Pattern.compile("\\s-s?n\\s*(.*?)\\s*-C\\s+\\d+$");
Matcher matcher = pattern.matcher(s);
if (matcher.find()){
System.out.println(matcher.group(1));
}
// => D:\workdir\PV 81\config\sum81pv.pwf
See the IDEONE Demo
If the -C <NUMBER>
is optional at the end, wrap with an optional group -> (?:\\\\s*-C\\\\s+\\\\d+)?$
.
Pattern details :
\\\\s
- a whitespace -s?n
- a -sn
or -n
(as s?
matches an optional s
) \\\\s*
- 0+ whitespaces (.*?)
- Group 1 matching any 0+ chars other than a newline \\\\s*
- ibid -C
- a literal -C
\\\\s+
- 1+ whitespaces \\\\d+
- 1 or more digits $
- end of string.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.