Query to find the salary of an employee

Question

I'm writing a query in Oracle as follows

select rownum as Salary, (rownum + 1) as Increment,(rownum + (rownum + 1)) as Total from dual;

And result is as follows

Salary   Increment   Total
---------------------------
    1            2        3

But i'm trying for to get following result

Salary   Increment   Total
---------------------------
    1            2        3
    3            2        5
    5            2        7

Here in above result Total of 1st row will become salary in the next row, Increment amount will be 2 for an instance, and total of 2nd row will become salary in the 3rd row and so on. help me in getting this result.

Answer 1

This query will give you that result. Use connect by level to create 3 rows. Use lag() to retrieve previous total. I honestly don't know if this is what you are looking for.

select nvl(lag(totalAux) over (order by SalaryAux), SalaryAux) as Salary,
       increament,
       totalAux as Total
  from (
  SELECT level        AS SalaryAux,
          2           AS Increament,
        (level * 2)+1 AS TotalAux
  FROM dual
  connect by level <=3);

OUTPUT

    SALARY INCREAMENT      TOTAL
---------- ---------- ----------
         1          2          3
         3          2          5
         5          2          7