返回员工姓名和工资的查询是什么
SELECT Name, Salary FROM Minions
WHERE Salary = (SELECT Max(Salary) FROM Minions)
Note that this will return more than one row if there is more than one employee who have the same max salary
select name, salary from (select * from salary_table order by salary desc limit 1)
SELECT FirstName, max(salary)
FROM Employees
WHERE salary = (
SELECT max(salary)
FROM employees
)
GROUP BY FirstName
working in SQL SERVER 2012
If you are using an oracle database and only want a single "employee" then:
SELECT MAX( name ) KEEP ( DENSE_RANK LAST ORDER BY salary ASC ) AS name,
MAX( salary ) KEEP ( DENSE_RANK LAST ORDER BY salary ASC ) AS salary
FROM Minions;
(kudos to Neil N for his table name)
FIRST_VALUE
(or LAST_VALUE
) analytic function. LAST_VALUE
. Select e.name, e.salary from employee e where
not exists (select salary from employee e1 where e.salary < e1.salary)
This will of course return more than one record if there are multiple people with the max salary.
A couple of proprietary solutions
SELECT TOP 1 [WITH ties] Name, Salary
FROM employee
ORDER BY Salary DESC
SELECT Name, Salary
FROM employee
ORDER BY Salary DESC
LIMIT 1
And a standard one
WITH E AS
(
SELECT Name, Salary,
ROW_NUMBER() OVER (ORDER BY Salary DESC) RN /*Or RANK() for ties*/
FROM employee
)
SELECT Name, Salary FROM E WHERE RN=1
These type of queries (grouped operaions) can execute with sub query. Example
select *from emp where sal=(max(sal)from emp)
In case there are multiple rows with the same MAX number then you can just limit the number to desired number like this
SELECT Name, Salary FROM Minions
WHERE Salary = (SELECT Max(Salary) FROM Minions) LIMIT 1
Assuming only one employee has maximum salary
SQL Server:
select top 1 name, salary
from employee
order by salary desc
Oracle:
select name, salary
from employee
order by salary desc
limit 1
Above queries scans the table only once unlike other queries using subqueries.
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