How to ignore lower as well upper case of a word in python?

Question

I want to find Andy in the list. Either Andy comes in upper or lower case in string the program should return True

String1 ='Andy is an awesome bowler' 
String2 ='andy is an awesome bowler'
String3 ='ANDY is an awesome bowler'

I am doing in this way

if 'Andy' in String1:
   print ('success')
else:
    print("Nothing")

But it is working only for Andy not for andy or ANDY . I do not want to use Pattern matching. By using lower() the Andy can be converted to lower case but I need both at a time ignoring lower as well as upper case. Is it possible?

Answer 1

You can convert the string to uppercase or lowercase first:

String1 ='Andy is an awesome bowler' 
String2 ='andy is an awesome bowler'
String3 ='ANDY is an awesome bowler'

if 'andy' in String1.lower(): # or this could be if 'ANDY' in String1.upper():
    print('success')
else:
    print('Nothing')

Answer 2

If you are sure that you string contains only ascii characters, use the following approach:

if 'andy' in string1.lower():
    do something

If your comparision strings involve unicodedata:

import unicodedata

def normalize_caseless(text):
    return unicodedata.normalize("any_string", text.casefold())

def caseless_equal(left, right):
    return normalize_caseless(left) == normalize_caseless(right)