How to use the \n in java properly

Question

Whenever I compile and run my code, the output becomes a big mess and I would like if someone could show me how to make my output look good.

import java.util.*;
public class JavaApplication3 {
    static Scanner sc = new Scanner(System.in);
    public static void main(String[] args) {
        int NumPerHamper;
        int NumHampersMade;
        int NumItemsLeftOver;
        int NumAvalable;
        double ValuePerHamper;
        double ItemCost;
        double ValueAllotedHamper;
        double ValueItemsLeftOver;
        String name="";
        Date TheDate = new Date();

        System.out.println("Enter the number of avaliable mac and cheese");
        NumAvalable = sc.nextInt();

        System.out.println("Enter the number of items per hamper");
        NumPerHamper = sc.nextInt();

        System.out.println("Price Of Item");
        ItemCost = sc.nextDouble();

        NumHampersMade = NumAvalable / NumPerHamper;
        NumItemsLeftOver = NumAvalable % NumPerHamper;
        ValuePerHamper = NumPerHamper * ItemCost;
        ValueAllotedHamper = ValuePerHamper * NumHampersMade;
        ValueItemsLeftOver = NumItemsLeftOver * ItemCost;
        System.out.printf("\n");
        System.out.printf(TheDate + "\n");
        System.out.printf("Amount of Hampers Made: ", NumHampersMade,"\n");
        System.out.printf("The Items Left Over is: ", NumItemsLeftOver,"\n");
        System.out.printf("Each Value Of the Hampers are: $%.2f.", ValuePerHamper,"\n");
        System.out.printf("The Price Of All The Hampers Is: $%.2f.", ValueAllotedHamper,"\n");
        System.out.printf("The Value Of Mac And Cheese Is: $%.2f.", ValueItemsLeftOver,"\n");
    }
}

Answer 1

This isn't right:

System.out.printf("Each Value Of the Hampers are: $%.2f.", ValuePerHamper,"\n");

The first argument (the format string) is the string you actually print, after replacing "format specifiers", or placeholders. Format specifiers in that string, such as %.2f , get substituted with the other arguments. So the second argument, ValuePerHamper , is used for the first specifier, %.2f ; and the third argument, \\n , is used for the second specifier---um, except that there aren't any other specifiers, so it doesn't get used at all.

You want to put \\n in the format string:

System.out.printf("Each Value Of the Hampers are: $%.2f.\n", ValuePerHamper);

( printf also allows you to use %n instead of \\n , which is more portable since it will also work on Windows systems where going to a new line needs \\r\\n instead of \\n .)

Answer 2

You could use %n or \\n . Either of these should be in the first parameter in the printf() method like this.

System.out.printf("Each Value Of the Hampers are: $%.2f. %n", ValuePerHamper);
System.out.printf("The Price Of All The Hampers Is: $%.2f.%n", ValueAllotedHamper);
System.out.printf("The Value Of Mac And Cheese Is: $%.2f.%n", ValueItemsLeftOver);

And you are missing %d for the first 2 lines to display the values.

System.out.printf("Amount of Hampers Made: %d %n", NumHampersMade);
System.out.printf("The Items Left Over is: %d %n", NumItemsLeftOver);