How to find a string in between two varchar strings in SQL server?

Question

Consider below table, I should be able to get result as "A" when input any value between XYZ-00000001 and XYZ-00000005 for eg: XYZ-00000003 or XYZ-00000004

similarly when input is given as XYZ-00000008 value "B" should be resulted.

Answer 1

SELECT [NAME] FROM YourTable WHERE YourValue BETWEEN Val1 AND Val2

Answer 2

Use SUBSTRING AND CHARINDEX:

DECLARE @tblTest AS Table
(
    Name VARCHAR(50),
    VAl1 VARCHAR(50),
    VAl2 VARCHAR(50)
)

INSERT INTO @tblTest VALUES
('A','XYZ-00000001','XYZ-00000005'),
('B','XYZ-00000006','XYZ-00000012'),
('C','XYZ-00000013','XYZ-00000019'),
('D','XYZ-00000020','XYZ-00000025')


DECLARE @SerachText VARCHAR(50)='XYZ-00000021'

SELECT
    *
FROM @tblTest
WHERE 
    SUBSTRING(@SerachText,CHARINDEX('-',@SerachText)+1,LEN(@SerachText)) >=SUBSTRING(VAl1,CHARINDEX('-',VAl1)+1,LEN(VAl1))
    AND
    SUBSTRING(@SerachText,CHARINDEX('-',@SerachText)+1,LEN(@SerachText)) <=SUBSTRING(VAl2,CHARINDEX('-',VAl2)+1,LEN(VAl2))

Answer 3

You can separate columns in characters and numbers and then input the value for comparison. Below code will answer 'A' for the input number between 1 to 5.

SELECT NAME
FROM
(
select *, left(val1,3) VAL1_ALFA, left(val2,3) VAL2_ALFA,
cast(REPLACE( val1, SUBSTRING( val1, PATINDEX( '%[a-z]%', val1 ), 4 ),'') as int) val1_NUM,
cast(REPLACE( val2, SUBSTRING( val2, PATINDEX( '%[a-z]%', val2 ), 4 ),'') as int) val2_NUM from Your_Table
) A
WHERE 
4 BETWEEN val1_NUM AND VAL2_NUM