Using regex to match a specific pattern in Python

Question

I am trying to create regex that matches the following pattern:

Note : x is a number eg 2

Pattern:

u'id': u'x'                # x = Any Number e.g: u'id': u'2'

So far I have tried the folllowing:

Regex = re.findall(r"'(u'id':u\d)'", Data)

However, no matches are being found.

Answer 1

This regex will match your patterns:

u'id': u'(\\d+)'

The important bits of the regex here are:

• the brackets () which makes a capture group (so you can get the information
• the digit marker \\d which specifies any digit 0 - 9
• the multiple marker + which means "at least 1"

Tested on the following patterns:

u'id': u'3'
u'id': u'20'
u'id': u'250'
u'id': u'6132838'

Answer 2

You have misplaced single quotes and you should use \\d+ instead of just \\d :

>>> s = "u'id': u'2'"
>>> re.findall(r"u'id'\s*:\s*u'\d+'", s)
["u'id': u'2'"]

Answer 3

Try this:

str1 = "u'id': u'x'"

re.findall(r'u\\'id\\': u\\'\\d+\\'',str1)

You need to escape single-quote(') because it's a special character