How to write sql query for show one data record from multi data record (LIKE or IN)?

Question

cite_name

1. London
2. Karachi
3. New York ...

city_type

1. 1,2,3

2. 2,3

3. 3,4

how to write query to find the all cities having city_type like 3?

Answer 1

SELECT* FROM [your_table] WHERE city_type LIKE '%3%'

Answer 2

Use FIND_IN_SET

select * from [your_table] where FIND_IN_SET(city_type,'3') > 0 

Note : Storing more than one value in single column separated by comma is bad way to store information. Consider changing your table structure. Have a separate table for CITY_TYPE and map it with your table for each CITY in separate rows

Answer 3

只需在开始和结束时使用带有通配符的LIKE ，就像这样

SELECT * FROM TABLE_NAME WHERE city_type LIKE '%3%';