inheritance using parent class method without calling parent class

Question

Is there any way to access parent class method, without actually calling the class?

eg:

1)

class A():
    def __init__(self):
        print('A class')

    def name():
        print('name from A class')

2)

class B(A):
    # I want to make use of name without actually calling or running A.
    # Is there any way to do that?

Answer 1

Yeah, you can just call it directly. This works fine:

class A():
    def __init__(self):
        print('A class')

    def name(self):
        print('name from A class')

class B(A):
    pass

B().name()

> A class
> name from A class

You can also use it inside of the class, like

class B(A):
    def b_name(self):
        print('I am B!')
        self.name()

If what you're trying to get around is calling A's init , then maybe you should turn name into a classmethod:

class A():
    def __init__(self):
        print('A class')

    @classmethod
    def name(self):
        print('name from A class')

A.name()

> name from A class

Alternatively, you can give B an init which doesn't call its super class, thus instantiating it without calling A's init. I don't particularly recommend this method:

class A():
    def __init__(self):
        print('A class')

    def name(self):
        print('name from A class')

class B(A):
    def __init__(self):
        print('B class')

    def b_name(self):
        print('b_name from B class')
        self.name()

B().b_name()

> B class
> b_name from B class
> name from A class