Replace string in a file using batch script. I have the below code but it's adding blank space at the end of each line

Question

Replace string in a file using batch script. I have the below code but it's adding blank space at the end of each line. It is affecting the job process while loading. Is there any easy way to replace like replace in notepad?

@ECHO OFF
setlocal enabledelayedexpansion
set "search=%Old text"
set "replace=%new text"
set txtfile=D:\new_%date:~-7,2%%date:~-10,2%%date:~-4,4%.txt
set newfile=D:\new_D%date:~-7,2%%date:~-10,2%%date:~-4,4%_T%time:~-11,2%%time:~-8,2%%time:~-5,2%.txt
if exist "%newfile%" del /f /q "%newfile%"
for /f "tokens=*" %%a in (%txtfile%) do (
set newline=%%a
set newline=!newline:%search%=%replace%!
echo !newline! >> %newfile%

)
copy %newfile% %textfile%

Answer 1

try to replace this :

echo !newline! >> %newfile%

by this :

>>%newfile% echo !newline!

EDIT : You'll better use (echo !newline!) like proposed by @MC ND

EDIT II : If you want something quicker (for big file) use a BAT/Powershell

@echo off
setlocal
set $source=%cd%\out.txt
set $Dest=%cd%\out1.txt

set "search=Old"
set "replace=New"

for /f "delims=" %%a in ('powershell -c "(get-content '%$source%') | foreach-object {$_ -replace '%Search%', '%replace%'} | set-content '%$dest%'"') do echo %%a