RegEx to extract text between tags in Java

Question

I need to extract the values after :70: in the following text file using RegEx. Value may contain line breaks as well.

My current solution is to extract the string between :70: and : but this always returns only one match, the whole text between the first :70: and last : .

:32B:xxx,
:59:yyy
something
:70:ACK1
ACK2
:21:something
:71A:something
:23E:something
value
:70:ACK2
ACK3
:71A:something

How can I achive this using Java? Ideally I want to iterate through all values, ie

ACK1\\nACK2 , ACK2\\nACK3

Thanks :)

Edit: What I'm doing right now,

Pattern pattern = Pattern.compile("(?<=:70:)(.*)(?=\n)", Pattern.DOTALL);
Matcher matcher = pattern.matcher(data);
while (matcher.find()) {
   System.out.println(matcher.group())
}

Answer 1

Try this.

String data = ""
    + ":32B:xxx,\n"
    + ":59:yyy\n"
    + "something\n"
    + ":70:ACK1\n"
    + "ACK2\n"
    + ":21:something\n"
    + ":71A:something\n"
    + ":23E:something\n"
    + "value\n"
    + ":70:ACK2\n"
    + "ACK3\n"
    + ":71A:something\n";
Pattern pattern = Pattern.compile(":70:(.*?)\\s*:", Pattern.DOTALL);
Matcher matcher = pattern.matcher(data);
while (matcher.find())
    System.out.println("found="+ matcher.group(1));

result:

found=ACK1
ACK2
found=ACK2
ACK3

Answer 2

You need a loop to do this.

Pattern p = Pattern.compile(regexPattern);
List<String> list = new ArrayList<String>();
Matcher m = p.matches(input);
while (m.find()) {
    list.add(m.group());
}

As seen here Create array of regex matches