How to pass an integer as an argument in Shell function and retrieve it

Question

I have a small function like this -

#! /bin/sh
function hey() {
    a=$1
    echo $a
}

x=2
hey x

As per my understanding it should print 2 but it is printing x . How to resolve it?

Answer 1

Running you code in my bash (not sh) , it also prints x. But if i change the last line to

hey $x 

then it prints 2.