I am searching for the regular expression that can find rows in an Oracle database. The rows contain a string that looks like this:
<?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
<characteristics>
<characteristic id="1001" mandatory="true" seq="1">
<wildcard/>
</characteristic>
<characteristic id="10001" mandatory="false" seq="1">
<value negation="false" seq="1">63</value>
</characteristic>
<characteristic id="10002" mandatory="false" seq="1">
<value negation="false" seq="1">64</value>
</characteristic>
<characteristic id="10051" mandatory="false" seq="1">
<value negation="false" seq="1">65</value>
</characteristic>
<characteristic id="10052" mandatory="false" seq="1">
<value negation="false" seq="1">66</value>
</characteristic>
<characteristic id="1010" mandatory="false" seq="100">
<wildcard/>
<value negation="false" seq="1">314</value>
</characteristic>
</characteristics>
The regular expression has to find all rows, that contain characteristics with special ids that contain a wildcard:
<wildcard/>
For Example: I want to get all rows, that contain the characteristics with ids 1000 and 1001 with wildcard. That means there must be the two strings
<characteristic id="1001" ...
<wildcard/>
...
</characteristic>
and
<characteristic id="1000" ...
<wildcard/>
...
</characteristic>
in it. Thereby the two strings can be in different orders.
Assuming the data is stored as XMLtype
select *
from t
where EXISTSNODE(doc,'/characteristics/characteristic[@id="1000"]/wildcard') = 1
and EXISTSNODE(doc,'/characteristics/characteristic[@id="1001"]/wildcard') = 1
;
Alternative syntax (as suggested by @Tomalak)
select *
from t
where EXISTSNODE(doc,'/characteristics[characteristic[@id="1001"]/wildcard and characteristic[@id="1010"]/wildcard]') = 1
For learning purposes, in case the data is stored as string
select *
from (select xmltype(doc) as doc from t)
where EXISTSNODE(doc,'/characteristics/characteristic[@id="1000"]/wildcard') = 1
and EXISTSNODE(doc,'/characteristics/characteristic[@id="1001"]/wildcard') = 1
;
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