Javascript if characters in a string has the same count occurance

Question

How to find if all distinct characters in a sting have the same count for example aassdd has the same count of 'a', 's' and 'd' . I know how to compare characters to each other but i don't know where to hold the numbers of each occurance

  function letterCount(string, letter, caseSensitive) {
      var count = 0;
      if ( !caseSensitive) {
        string = string.toUpperCase();
        letter = letter.toUpperCase();
      }
      for (var i=0, l=string.length; i<string.length; i += 1) {
        if (string[i] === letter) {
            count += 1;
        }
      }
      return count;
    }

My question is how to hold the number of each character occurance and than to compare them

Answer 1

You could use an object and the characters as property for count.

 function letterCount(string, caseSensitive) { var count = {}; if (!caseSensitive) { string = string.toUpperCase(); } for (var i = 0, l = string.length; i < l; i++) { if (!count[string[i]]) { count[string[i]] = 0; } count[string[i]]++; } return count; } console.log(letterCount('aAssdD', false)); console.log(letterCount('aAssdD', true));