In ruby, how to find the index of first non-whitespace character of given string

Question

In ruby, how to find the index of first non-whitespace (non-tab, non-space, non-newline) character of given string.

For example, given string "\\t\\nstring" , the index of first non-tab, non-space, non-newline character will be 2 which is 's'.

Answer 1

With this notation:

/\S/ =~ "\t\nstring"
# => 2

Answer 2

Try this one. s is your string

s.index(s.lstrip[0])