How can I get the pixels matrix of an image without using numpy?

Question

I'd like to find a way of getting the pixels matrix without using numpy . I'm aware that using with the code

from PIL import Image  

import numpty as np  

img = Image.open('example.png', 'r')  

pixels = np.array(img)

pixels get the pixels matrix of the image. However, I'd like to find a way without using numpy to get the pixels image without using the package numpy . Thanks in advance!

Answer 1

You can use the Image methods getdata(band=None) or getpixel(xy) .

In [1]: from PIL import Image

In [2]: im = Image.open('block.png', 'r')

In [3]: data = list(im.getdata())

In [4]: data[:20]
Out[4]: 
[(0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (144, 33, 33),
 (144, 33, 33),
 (144, 33, 33),
 (144, 33, 33),
 (255, 255, 255),
 (255, 255, 255),
 (255, 255, 255),
 (255, 255, 255),
 (0, 0, 0)]

In [5]: pxl = im.getpixel((1, 1))

In [6]: pxl
Out[6]: (144, 33, 33)

To convert the sequence returned by getdata() to a list of lists, you can use a list comprehension:

In [61]: data2d = [data[i:i+im.width] for i in range(0, len(data), im.width)]

In [62]: data2d[0]  # row 0
Out[62]: 
[(0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0),
 (0, 0, 0)]

In [63]: data2d[1]  # row 1
Out[63]: 
[(0, 0, 0),
 (144, 33, 33),
 (144, 33, 33),
 (144, 33, 33),
 (144, 33, 33),
 (255, 255, 255),
 (255, 255, 255),
 (255, 255, 255),
 (255, 255, 255),
 (0, 0, 0)]

In [64]: data2d[1][1]
Out[64]: (144, 33, 33)