how to find the smallest square surface for a specific city in array java

Question

public clas Qyteti {
    public float getSiperfaqja() {
        return siperfaqja;
    }
}


public clas Shteti {
    Qyteti [] qytetet;

    public void qytetiMeIVogel() {

    }
}

This is my code, i created an obj array named qytetet My homework is to find the smallest city in array calculating by square surface. qytetiMeIVogel should to calculate the smallest square surface.

qyteti = city

siperfaqja = square surface

Answer 1

There isn't really much to go on, but here is how I would do it:

    public class City {
    private  int squareSpace[];
    public void getData(){
      Scanner sc = new Scanner(System.in);
      squareSpace[] = new int[10];
      System.out.println("Please enter the square spaces of 10 cities\n");
      for(int i=0;i<10;i++) {
        sqaureSpace[i]=sc.nextInt();
      }
      //sc.close();
    }
    public int findMin(){
      int minValue=squareSpace[0];
      for(int i=1;i<10;i++) {
        if(squareSpace[i]<minValue)
          minValue=squareSpace[i];
    }
 }

I have assumed a static value of 10 here, but you can go ahead and assume any value. Now all you need to do is call the getData() and findMin() wherever required.