Replace all characters in string beside a-z 0-9 and ,

Question

嘿，我想清理一个字符串，只允许它具有az AZ（还有其他语言，不仅是英语），而且，我尝试执行ReplaceAll([^az 0-9,])但它正在删除其他语言。有人告诉我如何才能仅对特殊字符进行消毒，并且也不会从中删除表情符号？

Answer 1

You could try getting the az and 0-9 characters' ASCII code, and if the current character is not one of them, do what you wish. On how to get the ascii value of a character, refer here .

EDIT: the idea is that az and 0-9 the characters are next to each other. So just write a simple function that returns a boolean whether your current character is one of these, and if not, replace. For this though, you will have to replace one by one.

Answer 2

I've tested this regular expression and AFAIK it works...

String result = yourString.replaceAll("[^a-zA-Z0-9]", "");

It replaces any character that isn't in the set az, AZ, or 0-9 with nothing.

Answer 3

In java you can do

yourString.replaceAll("[^\\p{L}\\p{Nd}]+", "");

The regular expression [^\\p{L}\\p{Nd}]+ match all characters that are no a unicode letter or a decimal number.

If you need only characters (not numbers) you can use the regular expression [^\\\\p{L}]+ as follow:

yourString.replaceAll("[^\\p{L}]+", "");