I am trying to remove all the leading zero from the number part of a string. I have came up with this code (below). From the given example it worked. But when I add a '0' in the begining it will not give the proper output. Anybody know how to achive this? Thanks in advance
input: (2016)abc00701def00019z -> output: (2016)abc701def19z -> resut: correct
input: 0(2016)abc00701def00019z -> output: (2016)abc71def19z -> result: wrong -> expected output: (2016)abc701def19z
EDIT: The string can contain other than english alphabet.
String localReference = "(2016)abc00701def00019z";
String localReference1 = localReference.replaceAll("[^0-9]+", " ");
List<String> lists = Arrays.asList(localReference1.trim().split(" "));
System.out.println(lists.toString());
String[] replacedString = new String[5];
String[] searchedString = new String[5];
int counter = 0;
for (String list : lists) {
String s = CharMatcher.is('0').trimLeadingFrom(list);
replacedString[counter] = s;
searchedString[counter++] = list;
System.out.println(String.format("Search: %s, replace: %s", list,s));
}
System.out.println(StringUtils.replaceEach(localReference, searchedString, replacedString));
str.replaceAll("(^|[^0-9])0+", "$1");
这将删除非数字字符之后和字符串开头的任何零行。
java has \\P{Alpha}+, which matches any non-alphabetic character and then removing the the starting Zero's.
String stringToSearch = "0(2016)abc00701def00019z";
Pattern p1 = Pattern.compile("\\P{Alpha}+");
Matcher m = p1.matcher(stringToSearch);
StringBuffer sb = new StringBuffer();
while(m.find()){
m.appendReplacement(sb,m.group().replaceAll("\\b0+",""));
}
m.appendTail(sb);
System.out.println(sb.toString());
output:
(2016)abc701def19z
I tried doing the task using Regex and was able to do the required according to the two test cases you gave. Also $1 and $2 in the code below are the parts in the () brackets in preceding Regex.
Please find the code below:
public class Demo {
public static void main(String[] args) {
String str = "0(2016)abc00701def00019z";
/*Below line replaces all 0's which come after any a-z or A-Z and which have any number after them from 1-9. */
str = str.replaceAll("([a-zA-Z]+)0+([1-9]+)", "$1$2");
//Below line only replace the 0's coming in the start of the string
str = str.replaceAll("^0+","");
System.out.println(str);
}
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.