Read Value from Config File Python

Question

I have a file .env file contain 5 lines

DB_HOST=http://localhost/
DB_DATABASE=bheng-local
DB_USERNAME=root
DB_PASSWORD=1234567890
UNIX_SOCKET=/tmp/mysql.sock

I want to write python to grab the value of DB_DATABASE I want this bheng-local

---

I would have use

import linecache
print linecache.getline('.env', 2)

But some people might change the order of the cofigs, that's why linecache is not my option.

---

I am not sure how to check for only some strings match but all the entire line, and grab the value after the = .

I'm kind of stuck here :

file = open('.env', "r")
read = file.read()
my_line = ""

for line in read.splitlines():
    if line == "DB_DATABASE=":
        my_line = line
        break
print my_line

Can someone please give me a little push here ?

Answer 1

Have a look at the config parser: https://docs.python.org/3/library/configparser.html

It's more elegant than a self-made solution

Answer 2

Modify your .env to

[DB]
DB_HOST=http://localhost/
DB_DATABASE=bheng-local
DB_USERNAME=root
DB_PASSWORD=1234567890
UNIX_SOCKET=/tmp/mysql.sock

Python code

#!/usr/local/bin/python
import configparser
config = configparser.ConfigParser()
config.read('test.env')
print config.get('DB','DB_DATABASE')

Output:

bheng-local

Read https://docs.python.org/3/library/configparser.html

Answer 3

This should work for you

#!/usr/local/bin/python
file = open('test.env', "r")
read = file.read()

for line in read.splitlines():
    if 'DB_DATABASE=' in line:
        print line.split('=',1)[1]

Answer 4

#!/usr/local/bin/python

from configobj import ConfigObj
conf = ConfigObj('test.env')
print conf['DB_DATABASE']

Answer 5

from os import environ, path
from dotenv import load_dotenv

basedir = path.abspath(path.dirname(__file__))
load_dotenv(path.join(basedir, '.env'))
DB_DATABASE = environ.get('DB_DATABASE')
print(DB_DATABASE)

This could be another option