I have the following Jquery code that sends a ajax request to add-to-cart.php.
var productData = {
"product_id": s_product_id,
"product_opties": s_product_opties,
"product_aantal": s_product_aantal
}
productData = JSON.stringify(productData);
$.ajax({
url: 'inc/add-to-cart.php',
dataType: "json",
contentType: "application/json; charset=utf-8",
data: productData,
type: 'POST',
success: function(response) {
alert(response.d);
},
error: function(e){
console.log(e);
}
});
Add-to-cart.php:
<?php
print $_POST['product_id'];
?>
I am having two problems, the first one is that the $_POST['product_id'] does not exists when i ask for it and secondly when the ajax response returns it goes directly to the error: function and not succes function
The console log says:
[object Object]{readyState: 4, responseText: "<br /> <b>N...", status: 200, statusText: "OK"}
If the status is OK why does it jump to the error: part?
Thanks!
Try with:
...
var productData = {
'product_id': s_product_id,
'product_opties': product_opties,
'product_aantal': product_aantal,
}
$.ajax({
url: 'inc/add-to-cart.php',
dataType: 'json',
data: productData,
type: 'POST',
success: function(response) {
console.log(response.d);
},
error: function(e){
console.log(e);
}
});
...
Omitting the AJAX contentType
parameter and the part where you stringify your JSON, that's already ready to be sent to your url
, so, isn't needed.
Remove the line
productData = JSON.stringify(productData);
Then do not return HTML <br> ...
from add_to_cart.php
, you need to return a JSON string created by the PHP function json_encode
and NOTHING ELSE.
Like in:
<?php echo json_encode(array('d' => 'value of d'));
First: status Code from the Webserver is 200 cause he deliverd an existing site. Second: You dont need to stringify the json object by urself
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