Say I have wordsandnumbers!morestuff!morelettersandnumbers
, I want to get everything after the last !
(meaning there may be more than 2 !
). How can I do this using regex?
您可以使用$
将正则表达式匹配项锚定到字符串的末尾,然后使用所有连续的非感叹号(直到该点为止):
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