I have the following Dictionary Object:
Input = {'userName': ['psrr_api@auto-grid.com', 'ps_api1@auto-grid.com'],
'password': ['Everseeource2016!', 'Eversource2016!']}
Which will then result in this specific output:
output = [{'UserName':'ps_api@auto-grid.com','password': 'Eversource2016!'},
{'userName':'ps_api1@auto-grid.com','password':'Eversource2016!'}]
I'm not sure how I would approach this problem and any help would be appreciated.
Use a zip
to iterate over two lists as the same time. Use a dict constructor
to create individual dictionaries, inside a list comprehension
to handle automatically looping.
Input = {'userName': ['psrr_api@auto-grid.com', 'ps_api1@auto-grid.com'], 'password': ['Everseeource2016!', 'Eversource2016!']}
Output = [ {'UserName':u, 'password':p} for u,p in zip(Input['userName'], Input['password']) ]
In many NoSQL engines data is generally stored in a nested way, for your case it would be:
{'ID_1':
{
'username':'psrr_api@auto-grid.com',
'password': 'Everseeource2016'
},
'ID_2':{
'username':'ps_api1@auto-grid.com',
'password': 'Eversource2016!'
}
}
This provides an efficient way to access the data through the ID's
Here's the code for converting the format: This code is generic - means you don't have to specify the keys, in this case: username
and password
,
from collections import defaultdict
data = defaultdict(dict)
for idx in range(len(Input.values()[0])):
for key in Input.keys():
data['ID_'+str(idx)].update({key: Input[key][idx]})
print data
And if by chance you need a variable number of keys, you can generalize to:
Code:
keys = [(k,) * len(data[k]) for k in data.keys()]
data_vals = [data[k] for k in data.keys()]
output = [dict(kv) for kv in
(zip(*pairs) for pairs in zip(zip(*keys), zip(*data_vals)))]
Test Code:
data = {'userName': ['psrr_api@auto-grid.com', 'ps_api1@auto-grid.com'],
'password': ['Everseeource2016!', 'Eversource2016!']}
for i in output:
print(i)
Output:
{'userName': 'psrr_api@auto-grid.com', 'password': 'Everseeource2016!'}
{'userName': 'ps_api1@auto-grid.com', 'password': 'Eversource2016!'}
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